Hay, TNL, Help Me with My Homework
I haven't gone home yet because I have literally one problem left on this assignment I want to hand in, and today's the last day I can hand it in.
I need to use the formal definition of a limit to prove (epsilon delta style) that the limit as x approaches 5 of sqrt(x) = sqrt(5).
So I start with |sqrt(x)-sqrt(5)| < epsilon, right?
And then I multiply by the conjugate to get |x-5|/(sqrt(x)+sqrt(5)).
And since sqrt(x)+sqrt(5) > sqrt(5) > 1, |x-5|/(sqrt(x)+sqrt(5)) < |x-5|, I think. delta is 1 in the above, I think...
But then what? ;_;